Basic SQL 1 - SELECT, WHERE, GROUP BY

Jake Feldman

Plotting Practice

We will work with a built in data frame called chickweights

  1. Create a boxplot for the weights of the chicks by feed

  2. Create a plot that shows how many chickens received each type of feed.

head(chickwts)
  weight      feed
1    179 horsebean
2    160 horsebean
3    136 horsebean
4    227 horsebean
5    217 horsebean
6    168 horsebean
str(chickwts)
'data.frame':   71 obs. of  2 variables:
 $ weight: num  179 160 136 227 217 168 108 124 143 140 ...
 $ feed  : Factor w/ 6 levels "casein","horsebean",..: 2 2 2 2 2 2 2 2 2 2 ...

Plotting Practice Solutions

  1. Create a boxplot for the weights of the chicks by feed
ggplot(chickwts, aes(feed, weight)) + geom_boxplot()

  1. Create a plot that shows how many chickens received each type of feed.
ggplot(chickwts, aes(feed)) + geom_bar() + 
  labs(title= "Number of Chicks Receiving Each Feed")

Plotting two data frames on one graph

#First lets create a data frame that has the info sorted by the number of cylinders
mtcars_sorted_bycyl = mtcars[order(mtcars$cyl),]
mtcars_4cyl=mtcars_sorted_bycyl[1:11,]
mtcars_6cyl=mtcars_sorted_bycyl[12:18,]

#This is how we can plot things from teo different data frames
plot = ggplot() + geom_point(data = mtcars_4cyl, aes(hp, mpg ,color = "4 cylinder")) + 
geom_point(data = mtcars_6cyl, aes(hp, mpg, color = "6 cylinder")) +
scale_colour_manual(values = c("4 cylinder"="blue", "6 cylinder"="red"))  
plot

Structured Query Language (SQL)

-We will be using an R package called sqldf to issue our SQL queries

-We will use SQL to filter/sort/group rows of a data frame(s).

-We will keep adding on tools that we can use within SQL queries

-The syntax here is the exact same as if you were working with a MySQL database

head(mtcars)
                   mpg cyl disp  hp drat    wt  qsec vs am gear carb
Mazda RX4         21.0   6  160 110 3.90 2.620 16.46  0  1    4    4
Mazda RX4 Wag     21.0   6  160 110 3.90 2.875 17.02  0  1    4    4
Datsun 710        22.8   4  108  93 3.85 2.320 18.61  1  1    4    1
Hornet 4 Drive    21.4   6  258 110 3.08 3.215 19.44  1  0    3    1
Hornet Sportabout 18.7   8  360 175 3.15 3.440 17.02  0  0    3    2
Valiant           18.1   6  225 105 2.76 3.460 20.22  1  0    3    1

Basic SELECT Statement

-I like to put SQL syntax in all caps for readability

-Query must be a string (so put it in double quotes)

-You must be querying from a data frame

-Package sqldf does not like periods in column names

-SQL queries using sqldf return data frames

-SELECT column_names FROM df_name

-We can do a lot with just the basic select statement

#Select all rows but specific columns
df = sqldf("SELECT mpg, cyl  FROM mtcars")
Loading required package: tcltk
head(df)
   mpg cyl
1 21.0   6
2 21.0   6
3 22.8   4
4 21.4   6
5 18.7   8
6 18.1   6
#Select all the columns + rows from mtcars
df = sqldf("SELECT * FROM mtcars")
head(df)
   mpg cyl disp  hp drat    wt  qsec vs am gear carb
1 21.0   6  160 110 3.90 2.620 16.46  0  1    4    4
2 21.0   6  160 110 3.90 2.875 17.02  0  1    4    4
3 22.8   4  108  93 3.85 2.320 18.61  1  1    4    1
4 21.4   6  258 110 3.08 3.215 19.44  1  0    3    1
5 18.7   8  360 175 3.15 3.440 17.02  0  0    3    2
6 18.1   6  225 105 2.76 3.460 20.22  1  0    3    1

-Sometimes it is useful to rename or alias columns. We can do this with the AS command.

#vs was ambiguous so here I gave it a more appropriate name
df = sqldf("SELECT mpg, cyl, vs AS Engine  FROM mtcars")
head(df)
   mpg cyl Engine
1 21.0   6      0
2 21.0   6      0
3 22.8   4      1
4 21.4   6      1
5 18.7   8      0
6 18.1   6      1
#Need to use single quotes when using alias that is more than one word
df = sqldf("SELECT mpg, cyl, vs AS 'Engine Type'  FROM mtcars")
head(df)
   mpg cyl Engine Type
1 21.0   6           0
2 21.0   6           0
3 22.8   4           1
4 21.4   6           1
5 18.7   8           0
6 18.1   6           1

More SELECT Stuff

#We can create new column that are functions of other columns
#using the SELECT statement
df = sqldf("SELECT mpg, cyl, (mpg/cyl) AS 'mpg per cyl'  FROM mtcars")
head(df)
   mpg cyl mpg per cyl
1 21.0   6    3.500000
2 21.0   6    3.500000
3 22.8   4    5.700000
4 21.4   6    3.566667
5 18.7   8    2.337500
6 18.1   6    3.016667
#Selecting only distinct rows. Can use this to clean the data or
#just look at unique rows
df = sqldf("SELECT cyl, am  FROM mtcars")
head(df)
  cyl am
1   6  1
2   6  1
3   4  1
4   6  0
5   8  0
6   6  0
#Using DISTINCT command
df = sqldf("SELECT DISTINCT cyl, am  FROM mtcars")
head(df)
  cyl am
1   6  1
2   4  1
3   6  0
4   8  0
5   4  0
6   8  1

Using Where

-Lets us filter rows based on one or more conditions

-SELECT column_names FROM df_name WHERE condition

-We’ll start with a single condition and then extend to multiple conditions

#Using WHERE command
df = sqldf("SELECT *  FROM mtcars WHERE cyl=4")
head(df)
   mpg cyl  disp hp drat    wt  qsec vs am gear carb
1 22.8   4 108.0 93 3.85 2.320 18.61  1  1    4    1
2 24.4   4 146.7 62 3.69 3.190 20.00  1  0    4    2
3 22.8   4 140.8 95 3.92 3.150 22.90  1  0    4    2
4 32.4   4  78.7 66 4.08 2.200 19.47  1  1    4    1
5 30.4   4  75.7 52 4.93 1.615 18.52  1  1    4    2
6 33.9   4  71.1 65 4.22 1.835 19.90  1  1    4    1
#Don't have to SELECT columns in where condition
df = sqldf("SELECT mpg, qsec FROM mtcars WHERE cyl=4")
head(df)
   mpg  qsec
1 22.8 18.61
2 24.4 20.00
3 22.8 22.90
4 32.4 19.47
5 30.4 18.52
6 33.9 19.90
#Using AND within WHERE clause: both conditions have to be true
#for the row to be selected
df = sqldf("SELECT *  FROM mtcars WHERE cyl=4 AND qsec < 19")
head(df)
   mpg cyl  disp  hp drat    wt  qsec vs am gear carb
1 22.8   4 108.0  93 3.85 2.320 18.61  1  1    4    1
2 30.4   4  75.7  52 4.93 1.615 18.52  1  1    4    2
3 27.3   4  79.0  66 4.08 1.935 18.90  1  1    4    1
4 26.0   4 120.3  91 4.43 2.140 16.70  0  1    5    2
5 30.4   4  95.1 113 3.77 1.513 16.90  1  1    5    2
6 21.4   4 121.0 109 4.11 2.780 18.60  1  1    4    2
#Using AND with an OR also: for OR we need one of the clauses to be true
df = sqldf("SELECT *  FROM mtcars WHERE (cyl=4 AND qsec < 19) OR cyl=6")
head(df, 10)
    mpg cyl  disp  hp drat    wt  qsec vs am gear carb
1  21.0   6 160.0 110 3.90 2.620 16.46  0  1    4    4
2  21.0   6 160.0 110 3.90 2.875 17.02  0  1    4    4
3  22.8   4 108.0  93 3.85 2.320 18.61  1  1    4    1
4  21.4   6 258.0 110 3.08 3.215 19.44  1  0    3    1
5  18.1   6 225.0 105 2.76 3.460 20.22  1  0    3    1
6  19.2   6 167.6 123 3.92 3.440 18.30  1  0    4    4
7  17.8   6 167.6 123 3.92 3.440 18.90  1  0    4    4
8  30.4   4  75.7  52 4.93 1.615 18.52  1  1    4    2
9  27.3   4  79.0  66 4.08 1.935 18.90  1  1    4    1
10 26.0   4 120.3  91 4.43 2.140 16.70  0  1    5    2

Using Group By

-Lets us aggregate rows that have similar features in specified columns

-SELECT function(column_names) FROM df_name WHERE condition GROUP BY column_name

-The function tells you how the rows will be aggregated: MIN, MAX, AVG, COUNT, STDEV

-We’ll start with a single condition and then extend to multiple conditions

-You don’t have to print out the column you condition on

#COUNT() counts the number of rows. Independent of the data that is in the row.
df = sqldf("SELECT COUNT(*)  FROM mtcars GROUP BY cyl")
df
  COUNT(*)
1       11
2        7
3       14
#When using GROUP BY we will generally want to alias
df = sqldf("SELECT COUNT(*) AS 'Cyl Counts'  FROM mtcars GROUP BY cyl")
df
  Cyl Counts
1         11
2          7
3         14
#Now we can see which rows correspond to each of the
#different numbers of cylinders
df = sqldf("SELECT cyl,COUNT(*)  FROM mtcars GROUP BY cyl")
df
  cyl COUNT(*)
1   4       11
2   6        7
3   8       14
#Get the avg. quarter mile time for automatic versus
#manual cars
df = sqldf("SELECT am,AVG(qsec)  FROM mtcars GROUP BY am")
df
  am AVG(qsec)
1  0  18.18316
2  1  17.36000
#Get the avg. quarter mile time for automatic versus
#manual cars by number of cylinders
df = sqldf("SELECT cyl, am, AVG(qsec)  FROM mtcars GROUP BY cyl, am")
df
  cyl am AVG(qsec)
1   4  0  20.97000
2   4  1  18.45000
3   6  0  19.21500
4   6  1  16.32667
5   8  0  17.14250
6   8  1  14.55000

Grouping By w/ Where Clause

-The WHERE filtering happens before the groups are formed.

#Get the avg. quarter mile time for automatic versus
#manual cars by number of cylinders
df = sqldf("SELECT cyl, am, AVG(qsec) AS Avg_qsec  FROM mtcars WHERE 
           cyl>4 GROUP BY cyl, am")
df
  cyl am Avg_qsec
1   6  0 19.21500
2   6  1 16.32667
3   8  0 17.14250
4   8  1 14.55000
#Get the avg. quarter mile time for automatic versus
#manual cars by number of cylinders
df = sqldf("SELECT cyl, am, AVG(qsec)  FROM mtcars WHERE 
           (cyl>4 OR qsec>15) GROUP BY cyl, am")
df
  cyl am AVG(qsec)
1   4  0  20.97000
2   4  1  18.45000
3   6  0  19.21500
4   6  1  16.32667
5   8  0  17.14250
6   8  1  14.55000

Playing Around with Grades

#Read in grades.csv
gradesFulldf =read.csv("Grades.csv")

head(gradesFulldf)
  X Previous_Part Participation1 Mini_Exam1 Mini_Exam2 Participation2
1 1            32              1       19.5         20              1
2 2            32              1       20.0         16              1
3 3            30              1       19.0         19              1
4 4            31              1       22.0         13              1
5 5            30              1       19.0         17              1
6 6            31              1       19.0         19              1
  Mini_Exam3 Final Grade partipationPercentage partipationFinal
1       10.0  33.0     A                     1                5
2       14.0  32.0     A                     1                5
3       10.5  33.0    A-                     1                5
4       13.0  34.0     A                     1                5
5       12.5  33.5     A                     1                5
6        8.0  24.0     B                     1                5
  MiniOnePercentage MiniOneFinal MiniTwoPercentage MiniTwoFinal
1             0.975        4.875         0.9523810    11.428571
2             1.000        5.000         0.7619048     9.142857
3             0.950        4.750         0.9047619    10.857143
4             1.100        5.500         0.6190476     7.428571
5             0.950        4.750         0.8095238     9.714286
6             0.950        4.750         0.9047619    10.857143
  MiniThreePercentage MiniThreeFinal examPercentage examFinal
1           0.8333333         12.500         0.8250    24.750
2           1.1666667         17.500         0.8000    24.000
3           0.8750000         13.125         0.8250    24.750
4           1.0833333         16.250         0.8500    25.500
5           1.0416667         15.625         0.8375    25.125
6           0.6666667         10.000         0.6000    18.000
  finalPercentage
1        90.55357
2        92.64286
3        88.48214
4        90.67857
5        90.21429
6        79.60714
  1. Write a query to find the total number of students in the class.
#Find the counts of each letter grade given
gradeCounts = sqldf("SELECT COUNT(*) FROM gradesFulldf")
gradeCounts
  COUNT(*)
1      153
  1. Write a query to find how many people received each letter grade
#Find the counts of each letter grade given
gradeCounts = sqldf("SELECT Grade, COUNT(*) AS Count FROM gradesFulldf GROUP BY Grade")
gradeCounts
  Grade Count
1     A    60
2    A+     2
3    A-    24
4     B    45
5    B+    16
6    B-     2
7    C+     4
#What if we want them in the correct order?
gradeCounts[order(gradeCounts$Grade),]
  Grade Count
1     A    60
3    A-    24
2    A+     2
4     B    45
6    B-     2
5    B+    16
7    C+     4
#Have to reset the order of the levels using the factor command
gradeCounts$Grade <- factor(gradeCounts$Grade, levels = c("A+", "A", "A-", "B+", "B", "B-", "C+"))

gradeCounts[order(gradeCounts$Grade),]
  Grade Count
2    A+     2
1     A    60
3    A-    24
5    B+    16
4     B    45
6    B-     2
7    C+     4
  1. Write a query to return the rows (and all the columns) for the students who scored below a 90% on the final but still got an A.
#Use WHERE clause with an AND . Don't need single quotes around A but good habit
AStudents = sqldf("SELECT * FROM gradesFulldf WHERE examPercentage <0.9 AND Grade = 'A' ")
  1. Create a histogram to show the distribution of final percentages for students scoring above 90% on the final.
#Get the final percentages of students who got at least 90% on the final
df_goodFinal = sqldf("SELECT finalPercentage FROM gradesFulldf WHERE examPercentage >= 0.9 ")

#Plot these percentages
goodFinal_distribution = ggplot(df_goodFinal, aes(finalPercentage))  +geom_histogram(binwidth = 2) +labs(title ="Percentage Breakdown for Good Finals")
goodFinal_distribution

5.Find the average mini exam scores for those who got a B+,B, and B-

#Get the averages the three types of B
avgMiniB = sqldf("SELECT Grade, AVG(MiniOnePercentage) AS avg_1, AVG(MiniTwoPercentage) AS avg_2, AVG(MiniThreePercentage) AS avg_3 FROM gradesFulldf
                 WHERE Grade = 'B+' OR Grade = 'B' OR Grade = 'B-' GROUP BY Grade")

avgMiniB
  Grade     avg_1     avg_2     avg_3
1     B 0.8872222 0.7841270 0.8231481
2    B+ 0.9328125 0.7976190 0.9114583
3    B- 0.5250000 0.6428571 0.5625000

Take Homes

-We can use SQL to manipulate the data for plotting or to do basic calculations.